15q^2+22Q+8=)

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Solution for 15q^2+22Q+8=) equation: 



15q^2+22+8=)

We move all terms to the left:

15q^2+22+8-())=0

We add all the numbers together, and all the variables

15q^2=0

a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$q=\frac{-b}{2a}=\frac{0}{30}=0$

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